How to Figure out if Prop Returns Value When Overrides Value

Hi,

It is possible to set several behaviors on the same method. In this case the last behavior set will be the default after the rest were used. For example:

[TestMethod]
[Isolated]
public void TwoConsecutiveCallsToWillReturn()
{
    var fakeProduct = Isolate.Fake.Instance<Product>();

    // Calling WhenCalled once cause the value to be the default return value
    Isolate.WhenCalled(() => fakeProduct.Price).WillReturn(20.0f);

    // this call cause the previous behavior to happen once and this behavior becomes the default returned value 
    Isolate.WhenCalled(() => fakeProduct.Price).WillReturn(15.0f);

    // Calling Price the 1st time return 20
    Assert.AreEqual(20.0f, fakeProduct.Price);

    // fakeProduct.Price will return 15 for the rest of the calls
    Assert.AreEqual(15.0f, fakeProduct.Price);
    Assert.AreEqual(15.0f, fakeProduct.Price);
}

In the case you have described where you want to fake the first call and use the original method after you can set two behaviors, for example:

public class Counter
{
    private int counter = 100;

    public int CountAndIncrement()
    {
        return counter++;
    }
}

[TestMethod]
public void CounterTest()
{
    var instance = Isolate.Fake.Instance<Counter>(Members.CallOriginal);
    Isolate.WhenCalled(()=>instance.CountAndIncrement()).WillReturn(0);
    Isolate.WhenCalled(()=>instance.CountAndIncrement()).CallOriginal();

    Assert.AreEqual(0, instance.CountAndIncrement());
    Assert.AreEqual(100, instance.CountAndIncrement());
    Assert.AreEqual(101, instance.CountAndIncrement());
}

Please note that in this test the Members.CallOriginal is used in the fake creation. If it's omitted then Isolate.WhenCalled(()=>instance.CountAndIncrement()).CallOriginal() will be ignored and the method will always return 0. We're investigating it to see if it's a bug.

Please let me know if it helps.

Best Regards,
Elisha
Typemock Support Team