Fake static method

Hi Timor, and welcome to the wonderful world of Typemock!

What you are trying to do is called behavior sequencing. That means you want to set a different behavior on each call to a method. The golden rule of behavior sequencing is that the final behavior setting remains the default for all subsequent calls. That's why the third call returns 1 - the last setting is to return 1.

(by the way, although you put the arguments inside the WhenCalled clause, Isolator disregards them- it just counts calls).

So how do we do this?

If you want the third call to exercise the real code, add a CallOriginal. In this example, I've removed the arguments, replaced them with empty string, because, like I said only the order of call counts:

Isolate.WhenCalled(() => MyStaticClass.GetValue("")).WillReturn(0); 
Isolate.WhenCalled(() => MyStaticClass.GetValue("")).WillReturn(1); 
Isolate.WhenCalled(() => MyStaticClass.GetValue("")).CallOriginal();

That will give you the result you want. But I think you're interested in another feature - you probably want to make sure when the argument is "else", then the real code will run. This is called conditional behavior. Here you specify the argument, with an addition to tell Isolator to run it only in the case of the correct arguments:

Isolate.WhenCalled(() => MyStaticClass.GetValue("")).WillReturn(0); 
Isolate.WhenCalled(() => MyStaticClass.GetValue("")).WillReturn(1);
Isolate.WhenCalled(() => MyStaticClass.GetValue("else")).WithExactArguments().CallOriginal();

This time we're telling Isolator to do CallOriginal only if the argument is "else".

I hope this was helpful. Let em know if you need further help.

Thanks,

Thansk Gilz for your help,

CallOriginal is exactly what I need.

I didn't know that the arguments are ignored, except if you call WithExactArguments.

Best regards,

Tim