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Using method groups with WhenCalled()

0 votes
It would be nice to be able to use method groups with Isolate.WhenCalled(). For example, if I change 

Isolate.WhenCalled(() => filterTest.InitState()).CallOriginal();

to 
Isolate.WhenCalled(filterTest.InitState).CallOriginal();


I get this error:
TypeMock.TypeMockException:
*** Cannot call Isolate.WhenCalled() with method group fake.InitState. Try using Isolate.WhenCalled( () => fake.InitState()) instead

Please consider this feature for a future release :)
asked by dblack
Report User
 (8.4k points)

2 Answers

0 votes
Hi,

Thank you for the suggestion, we will look into it.

Regards,
Alex,
Typemock Support.
answered by alex
Report User
 (17k points)
0 votes
If the suggestion is too hard, could the method signature be changed to
Expression<Action> and Expression<Func<T>>, please?

Code quality tools suggests method group as argument and that causes unit tests to fail.
answered by calin.pirtea
Report User
 (140 points)
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